I am a beginner in ASP.Net MVC 5 and I want to know how to upload file in database and the display them to the user. I saw numerous example on internet related to above question. But all talks about putting file in some solution folder. But I want to upload file to database and be able to retrieve it in "Details View".
Issue: I am able to upload file in Database, but I am not sure how to Display the file link to user. Clicking on which user should be able to view/download the uploaded file. Below is my attempt.
Model:
public class File
{
public int Id { get; set; }
[StringLength(255)]
public string FileName { get; set; }
public byte[] Content { get; set; }
}
Controller:
// GET: FileUpload
public ActionResult Create()
{
return View();
}
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create(File file, HttpPostedFileBase upload)
{
try
{
if (ModelState.IsValid)
{
if (upload != null && upload.ContentLength > 0)
{
var tempfile = new File
{
FileName = System.IO.Path.GetFileName(upload.FileName),
};
using (var reader = new System.IO.BinaryReader(upload.InputStream))
{
tempfile.Content = reader.ReadBytes(upload.ContentLength);
}
file.Content = tempfile.Content;
}
_context.Files.Add(file);
_context.SaveChanges();
return RedirectToAction("Index");
}
}
catch (RetryLimitExceededException /* dex */)
{
//Log the error (uncomment dex variable name and add a line here to write a log.
ModelState.AddModelError("", "Unable to save changes. Try again, and if the problem persists see your system administrator.");
}
return View(file);
}
public ActionResult Details(int? id)
{
if (id == null)
{
return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
}
File f1 = _context.Files.Where(f => f.Id == id).SingleOrDefault();
if (f1 == null)
{
return HttpNotFound();
}
// NOT SURE WHAT TO HERE
return View(f1);
}
View: Details.chtml file
@model fileupload.Models.File
<h4>File</h4>
@* NOT SURE HOW TO HANDLE THE FILE LINK HERE*@
So, In the database I can see some binary content entry in "Content" Column. But I am not sure how can I display some link in the detail section. I want to display the file link in the details view. Clicking on which the file will get downloaded or something like preview. Kindly guide me.
EDIT 1
public FileContentResult Download(int id)
{
var file = _context.Files.First(f => f.Id == id);
var fileRes = new FileContentResult(file.Content.ToArray(), "application/pdf");
fileRes.FileDownloadName = file.FileName;
return fileRes;
}
Assuming your code in your controller is correctly populating your model, you simply need base64
encode the image and display that.
@{
var encodedImage = Convert.ToBase64String(Model.Content);
var embeddedImage = $"data:image/png;base64,{encodedImage}";
}
<img src="@embeddedImage" />
Take a look at this question as well: MVC How to display a byte array image from model
Add below code in model :
public string imagePath { get; set; }
[Display(Description = "imgfile")]
[RegularExpression(@"([a-zA-Z0-9()\s_\\.\-:!@#$%^&])+(.png|.jpg|.gif|.bmp|.tiff|.PNG|.JPG|.GIF|.BMP|.TIFF)$", ErrorMessage = "Only Image files allowed.")]
public HttpPostedFileBase imgfile { get; set; }
In controller (This will validate your image for maore than 1mb from your action, if u want to validate it before post you can google it for jquery validations) :
if (userRegObj != null && userRegObj.imgfile != null && userRegObj.imgfile.FileName != null && userRegObj.imgfile.ContentLength > 1024000)//1 MB
{
TempData["msg"] = "danger~Profile Picture Should be Less Than 1 MB";
if (userRegObj.Id <= 0)
{
return View(userRegObj);
}
return RedirectToAction("Action", "Controller", new { id = userRegObj.Id });
}
else if (userRegObj != null && userRegObj.imgfile != null && userRegObj.imgfile.FileName != null)
{
string path = Path.Combine(Server.MapPath("~/Media/ProfilePics"), Path.GetFileName(userRegObj.imgfile.FileName)); // folder to save images
userRegObj.imagePath = Path.GetFileName(userRegObj.imgfile.FileName);
userRegObj.imgfile.SaveAs(path);
}
In view (This code will help you if your model having an image then it will show the image in the upload section else it will show a default image as you want to manage yourself) :
@if (Model != null && Model.Id>0 &&Model.imagePath!=null)
{
<div class="form-group">
<label for="exampleInputEmail1">Upload Your Image:<br /><small>(Width:155, Height:155)</small></label>
<span class="imageupld">
<img src="@Url.Content("~/Media/ProfilePics/"+Model.imagePath)" alt="obsequium" id="profilepic" style="margin-top:8.5px" />
</span>
<span class="file-up" style="overflow:hidden;">
<span class="pic" id="p">@Model.imagePath</span>
@Html.TextBoxFor(m => m.imgfile, new { @class = "profilepic", type = "file", data_value = "pic", tabindex = 17, accept = "image/*", id = "picVal", @onchange = "checkImage()" })
@Html.ValidationMessageFor(m => m.imgfile, "", new { @class = "text-red", id = "imgVal" })
</span>
</div>
}
else if (Model != null && Model.Id>0 && Model.imagePath == null )
{
<div class="form-group">
<label for="exampleInputEmail1">Upload Your Image:<br /><small>(Width:155, Height:155)</small></label>
<span class="imageupld">
<img src="@Url.Content("~/Content/Template/")images/imgupload.png" alt="obsequium" id="profilepic" style="margin-top:8.5px">
</span>
<span class="file-up" style="overflow:hidden;">
<span class="pic">Upload Image</span>
@Html.TextBoxFor(m => m.imgfile, new { @class = "profilepic", type = "file", data_value = "pic", tabindex = 17, accept = "image/*", id = "picVal", @onchange = "checkImage()" })
@Html.ValidationMessageFor(m => m.imgfile, "", new { @class = "text-red", id = "imgVal" })
</span>
</div>
}
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