Php to MySQL Database Connection

Question

Im not sure whats going wrong with this code. I have a paragraph stored in the database under content, but for some reason I can't get it to display. Any help would be greatly appreciated, I'm a newer developer and welcome any feedback.

<?php
require_once('db_connection.php'); //connection credentials

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);

$sql = "SELECT content FROM content";
$result = mysqli_query($conn, $sql);

while($row = mysqli_fetch_row($result)) { 
    echo $row;
}

mysqli_close($conn);
?>

Answer 1

echo $row; you're missing the column's object's array itself that you want to echo.

What you want is echo $row[0];

However, both column and table name are the same, so make sure that that is indeed correct.

As per the manual:

• http://php.net/manual/en/mysqli-result.fetch-row.php

Example pulled from the manual:

$query = "SELECT Name, CountryCode FROM City ORDER by ID DESC LIMIT 50,5";

if ($result = mysqli_query($link, $query)) {

    /* fetch associative array */
    while ($row = mysqli_fetch_row($result)) {
        printf ("%s (%s)\n", $row[0], $row[1]);
    }

    /* free result set */
    mysqli_free_result($result);
}

If the above failed, then that could mean that your query may have failed and you need to check for errors on the query, using mysqli_error($conn) .

Reference:

• http://php.net/manual/en/mysqli.error.php

Same thing goes for the connection.

Reference:

• http://php.net/manual/en/function.mysqli-connect.php

Example from the manual:

<?php
$link = mysqli_connect("127.0.0.1", "my_user", "my_password", "my_db");

if (!$link) {
    echo "Error: Unable to connect to MySQL." . PHP_EOL;
    echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
    echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
    exit;
}

echo "Success: A proper connection to MySQL was made! The my_db database is great." . PHP_EOL;
echo "Host information: " . mysqli_get_host_info($link) . PHP_EOL;

mysqli_close($link);
?>