vuex subscribe to individual mutation

Question

Is it possible to subscribe to an individual mutation?

Instead of:

this.$store.subscribe((mutation, state) => {
   if(mutation === 'someMutation'){
       doSomething()
   }
})

I would like something like this:

this.$store.subscribe('someMutation', state => {
    doSomething()
})

Answer 1

How about wrapping the method you have somewhere in Vue prototype?

So instead of having:

this.$store.subscribe((mutation, state) => {
   if(mutation === 'someMutation'){
       doSomething()
   }
})

You would have something like:

Vue.prototype.subscribeMutation = function(someMutation, someFunction) {
       this.$store.subscribe((mutation, state) => {
       if(mutation === someMutation){
           someFunction(state)
       }
    })
}

I haven't tested the code, but you should be able to get the working result easily.

Answer 2

From vuex docs:

The handler is called after every mutation and receives the mutation descriptor and post-mutation state as arguments.

It will react to all mutations, So you only can implement with your own conditional.

Answer 3

could you tell please what the reason have subscribtion to the mutation if the only work of mutation is changing store:

[types.MUTATE_SET_ACTIVE_TICKER]: (state, payload) => {
state.activeTicker = payload
},

and then you can take the data from the store in the component directly:

this.$store.state.activeTicker

Answer 4

Try something like this:

this.$store.subscribe(mutation => {
                if (mutation.type === 'setData') {
//  do something here
                }
            });