Example: I have a df in which the first column is
dat <- c("A","B","C","A")
and then I have another df in which I have in the first column is:
dat2[, 1]
[1] A B C
Levels: A B C
dat2[, 2]
[1] 21000 23400 26800
How can I add the values in the second df ( dat2
) to the first df ( dat
)? In the first df there are repetitions and I want that everytime there is an "A" it will add the corresponding value (21000) from the second df in a new column.
Generating reproducible dataframe...
dat1 <- data.frame(x1 = c("A","B","C","A"), stringsAsFactors = FALSE)
dat2 <- data.frame(x1 = c("A","B","C"),
x2 = c(21000, 23400, 26800), stringsAsFactors = FALSE)
Then use the match
function.
dat1$dat2_vals <- dat2$x2[match(dat1$x1, dat2$x1)]
It is important to transform your character columns to character
type rather than factor
type or the elements will not match. I mention this due to the levels
attribute in your dat2.
A third option which I prefer is left_join
from dplyr
... It seems to be faster than merge
with large data frames.
require(dplyr)
dat1 <- data.frame(x1 = c("A","B","C","A"), stringsAsFactors = FALSE)
dat2 <- data.frame(x1 = c("A","B","C"),
x2 = c(21000, 23400, 26800), stringsAsFactors = FALSE)
dat1 <- left_join(dat1, dat2, by="x1")
Let's race large dataframes with microbenchmark
, just for fun!
create large dataframes
dat1 <- data.frame(x1 = rep(c("A","B","C","A"), 1000), stringsAsFactors = FALSE)
dat2 <- data.frame(x1 = rep(c("A","B","C", "D"), 1000),
x2 = runif(1,0), stringsAsFactors = FALSE)
on your marks, get set, GO!
library(microbenchmark)
mbm <- microbenchmark(
left_join = left_join(dat1, dat2, by="x1"),
merge = merge(dat1, dat2, by = "x1"),
times = 20
)
Many, many seconds later.... left_join is MUCH faster for large dataframes.
Use merge
function.
# Input data
dat <- data.frame(ID = c("A", "B", "C", "A"))
dat2 <- data.frame(ID = c("A", "B", "C"),
value = c(1, 2, 3))
# Merge two data.frames by specified column
merge(dat, dat2, by = "ID")
ID value
1 A 1
2 A 1
3 B 2
4 C 3
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