I have been trying to set the content type for an xsl
file. This is what I have done so far
def xsl_content_type():
filename = static('sitemap.xsl')
response = HttpResponse(filename)
response['Content-Type'] = "text/xsl"
response['Content-Length'] = len(filename)
return response
This returns
HTTP/1.0 200 OK
Date: Wed, 13 Sep 2017 05:04:46 GMT
Server: WSGIServer/0.2 CPython/3.6.1
Last-Modified: Tue, 13 Jun 2017 03:54:17 GMT
Content-Length: 7134
Content-Type: application/octet-stream
Cache-Control: max-age=0, public
Access-Control-Allow-Origin: *
Even thought I did setup the Content-Type
as text/xsl
, all I get is application/octet-stream
. I have also tried doing response = HttpResponse(filename, content_type="text/xsl")
, but the content type is the same.
What am I missing here?
There could be a better way, but the following helped me
urls.py
add url(r'^sitemap\\.xsl', xsl_content_type, name='sitemap_xsl')
to urlpatterns
views.py
Add the following code:
def xsl_content_type(request):
"""
Converts the MIME type of `sitemap.xsl`.
Returns
-------
HttpResponse: HttpResponse
Returns `sitemap.xsl`.
"""
if 'DYNO' in os.environ:
url = os.path.join(settings.STATIC_URL, 'sitemap.xsl')
user_agent = 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.7) Gecko/2009021910 Firefox/3.0.7'
headers = {'User-Agent': user_agent, }
request = urllib.request.Request(url, None, headers)
response = urllib.request.urlopen(request)
data = response.read().decode('UTF-8')
else:
data = open(os.path.join(settings.STATIC_ROOT, 'sitemap.xsl')).read()
return HttpResponse(data, content_type="text/xsl")
Note: The DYNO
is a Heroku environment variable, you can add your own environment variable (if needed) when using in production.
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