I've been trying to post data using AJAX that will update a field in my database however I am having trouble doing so. Everything seems like it should run fine and I get no errors in the console but I've no idea why my db won't update.
Can someone help me out here please?
AJAX
:
function ajaxUpdate() {
var arr = {var1: name, var2: age};
$.ajax({
url: 'ajax/confirm.php',
type: 'POST',
data: JSON.stringify(arr),
contentType: 'application/json; charset=utf-8',
dataType: 'json',
success: function(data) {
console.log("success");
}
});
}
Confirm.php
:
$name=$_POST['var1'];
$age=$_POST['var2'];
if($name == "Stuart") {
mysqli_query($connection,"UPDATE people SET age='$age'");
}
else if($name == "Peter") {
mysqli_query($connection,"UPDATE people SET age='$age'");
}
The connection to my database is working as I have $connection
setup and went to the page /ajax/confirm.php
in my browser and I see "Connection successful" in my console as I defined if successful.
So I am unsure as to why this isn't updating?
Are my values not being posted correctly?
I'm new to AJAX so forgive me if this is something very simple!
Thanks
Try the following:
function ajaxUpdate() {
var arr = {var1: name, var2: age};
$.ajax({
url: 'ajax/confirm.php',
type: 'POST',
data: arr,
success: function(data) {
console.log("success");
}
});
}
Instead of converting the object into json string send it as is.
Edit: Also remove dataType
and probably contentType
too. Your code is at risk of SQL Injection. Look into prepared statements and escaping mysql
data.
Maybe this well help.
<script type="text/javascript">
function ajaxUpdate() {
var data = $('#formID').serialize();
$.ajax({
url: 'ajax/confirm.php',
type: 'POST',
data: data,
dataType: 'json',
encode : true,
success: function(data) {
if(data == "ok"){
console.log("success");
}else{
console.log(data);
}
}
});
}
</script>
confirm.php
<?php
$name = $_POST['name'];
$age = $_POST['age'];
switch ($name) {
case 'Stuart':
$sql = "UPDATE people SET age = ? WHERE name = ? ";
$stmt = mysqli_prepare($connection, $sql);
mysqli_stmt_bind_param($stmt, 'si', $name, $age);
if (mysqli_stmt_execute($stmt)) {
echo json_encode('ok');
} else {
echo json_encode(mysqli_stmt_error($stmt));
}
break;
case 'Peter':
$sql = "UPDATE people SET age = ? WHERE name = ? ";
$stmt = mysqli_prepare($connection, $sql);
mysqli_stmt_bind_param($stmt, 'si', $name, $age);
if (mysqli_stmt_execute($stmt)) {
echo json_encode('ok');
} else {
echo json_encode(mysqli_stmt_error($stmt));
}
break;
default:
echo json_encode('Unknown name ');
}
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