how to get all href links from web url
Question
I want to get all href links from a web url(url: http://localhost/test.php ) including file also because i have included one php file (menulink.php) my script is working only for outside of href and if condition checked href only.
<a href="test.html" title="test"></a>
<a href="test1.html" title="test1"></a>
<a href="menulink1.html" title="menulink1"></a>
<a href="menulink2.html" title="menulink2"></a>
if condition true:
<a href="test4.html" title="test4"></a>
<a href="menulink3.html" title="menulink3"></a>
but i want to get else condition also both time(i need all href links do not consider if else condition or whatever condition)
Missing href links:
<a href="http://www.google.com" title="test6"></a>
<a href="menulink5.html" title="menulink5"></a>
<a href="menulink6.html" title="menulink6"></a>
how can i do it?can you resolve from my code. This is my code:
index.html
$(document).ready(function(){
var url = "http://localhost/links/test.php";
var arr= null;
$.post('load.php', { url: url,async: false},
function(html) {
$('#page').html(html);
var links = $('a');
var title = $('a').attr('title');
var arr=[];
for(var i=0; i < links.length; i++)
{
arr.push(links[i]);
}
console.log(arr); //all href links//
} );
});
test.php
<html>
<head>
<title>Test</title>
</head>
<body>
<div>
<?php include("menulink.php"); ?>
<a href="test.html" title="test"></a>
<a href="test1.html" title="test1"></a>
<?php
$result_array="123";
if ($result_array=="123")
{
?>
<a href="test4.html" title="test4"></a>
<?php
}
else{
?>
<a href="http://www.google.com" title="test6"></a>
<?php
}
?>
</div>
</body>
</html>
load.php
<?php
$url = $_POST['url'];
$html = file_get_contents($url);
echo $html;
?>
menulink.php
<html>
<head>
<title>Test</title>
</head>
<body>
<div>
<a href="menulink1.html" title="menulink1"></a>
<a href="menulink2.html" title="menulink2"></a>
<?php
$result_array="123";
if ($result_array=="123")
{
?>
<a href="menulink3.html" title="menulink3"></a>
<?php
}
else{
?>
<a href="menulink5.html" title="menulink5"></a>
<a href="menulink6.html" title="menulink6"></a>
<?php
}
?>
</div>
</body>
</html>
i want to get all the href links. Do not consider if else conditions or whatever conditions from the url document.please resolve from my code.
2 answers
solution1
0 2017-10-10 20:09:26
Try this :
$dom = new DOMDocument;
$dom->validateOnParse = true;
$dom->loadHTML($html);
$links = array();
foreach($dom->getElementsByTagName('a'); as $link) {
$links[] = $link->getAttribute('href');
}
solution2
0 2017-10-10 20:35:59
// Create DOM from URL or file //you have to include simple_html_dom.php form above link
$html = file_get_html('http://www.google.com/');
// Find all links
You have to do this in load.php file as
include("simple_html_dom.php"); // please make sure right location of file
$url = $_POST['url'];
$html = file_get_html($url);
header('Content-Type: application/json');
$links = array();
foreach($html->find('a') as $element) {
$links[] = $element->href;
} echo json_encode($links);
and in jquery get those links
$(document).ready(function(){
var url = "http://localhost/links/test.php";
//var arr= null;
$.post('load.php', { url: url,async: false},
function(html) {
$('#page').html(html);
console.log(html);
} );
});
HTML
<html>
<head>
<title>Test</title>
</head>
<body>
<div>
<?php include("menulink.php"); ?>
<a href="test.html" title="test"></a>
<a href="test1.html" title="test1"></a>
<?php
get_links("123");
get_links("321");
function get_links($a){
?>
<?php
$result_array=$a;
if ($result_array=="123")
{
?>
<a href="test4.html" title="test4"></a>
<?php
}
else{
?>
<a href="http://www.google.com" title="test6"></a>
<?php
}
?>
<?php
}
}
?>
</div>
</body>
</html>
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