I was trying to make an ajax call and show an html part inside a div class. For that i used the following way.
$.ajax({
type: "get",
url: "{{url('searchByCheckbox')}}",
dataType: 'html',
success: function(html)
{
$(".infinite-scroll").html(html)
}
});
But the problem is there is a script inside that html part which i wanted to load when i make first ajax call it's not loaded but for the second one it's loaded the script. suppose the html response like this :
<script>
alert()
</script>
// html
How do i make it work? I put the script above the html page which i'm getting as response.
(those who are marking the Question as duplicate should read at least what i want and what they wanted )
Im sure that the error is happening because of the script, because you are closing the </script>
tag inside the html.
The best solution is to return the data from your ajax
call as a json
To do that you should:
1- add a dataType
to your ajax
parameter as the below:
$.ajax({
type: "get",
dataType: "json",
2- In the php
file handling the ajax
call, you must resurn the values as a json as below:
Assume that currently you are doing the following:
echo $html
You should change it to match the below:
$retArr = array(
"html" => $html, //Your html code without the javascript function
"jsFunc" => $jsFunc //Your java script function parameters
) ;
echo json_encode($retArr) ;
And then your ajax success
must be as the below:
success: function(data)
{ //You can access all the object parametes by calling the object name `data` followed by a dot `.` and then by the parameter key
data.jsFunc // Your javascript function params
$(".infinite-scroll").html(data.html) ;
}
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