I have a dataset containing a column "date":
date item
20.3.2010 17:08 a
20.3.2010 11:16 b
2010-03-20 15:55:14.060 c
2010-03-21 13:56:45.077 d
I would like to convert all values that have format as 20.3.2010 17:08
into 2010-03-21 13:56:45.077
.
Does anybody have an idea?
Thank you.
Check on below:
from datetime import datetime
INPUT_FORMAT = '%d.%m.%Y %H:%M'
OUTPUT_FORMAT = '%Y-%m-%d %H:%M:%S.%f'
datetime.strptime('20.3.2010 17:08',INPUT_FORMAT).strftime(OUTPUT_FORMAT)
#Output '2010-03-20 17:08:00.000000'
You could find more information in offcial strptime
and strftime
.
To do a 100% match with 3 digits microseconds you could use this SO approach .
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