Consider two lists, each with 10 elements:
list_one = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']
list_two = ['ok', 'good', None, 'great', None, None, 'amazing', 'terrible', 'not bad', None]
How can I create a list of tuples in which each tuple in the list contains two elements of the same index from each list -- but also, I need to skip the None values, so my final list of 6 tuples which should look like this:
final_list_of_tuples = [('a', 'ok'), ('b', 'good'), ('d', 'great'), ('g', 'amazing'), ('h', 'terrible'), ('i', 'not bad')]
I tried the following code, but it puts every single one of the strings from list_one into a tuple with all of the strings from list_two:
final_list_of_tuples = []
for x in list_one:
for y in list_two:
if y == None:
pass
else:
e = (x,y)
final_list_of_tuples.append(e)
You can use zip function to create the list of tuples and then remove the entries with None in it using a list comprehension.
[w for w in zip(list_one, list_two) if None not in w]
Outputs:
[('a', 'ok'), ('b', 'good'), ('d', 'great'), ('g', 'amazing'), ('h', 'terrible'), ('i', 'not bad')]
This skips pairs where the corresponding item in the second list is None
:
final_list_of_tuples = [(a, b) for (a, b) in zip(list_one, list_two) if b is not None]
And here's one possible for
loop version:
final_list_of_tuples = []
for i, b in enumerate(list_two):
if b is not None:
a = list_one[i]
final_list_of_items.append((a, b))
>>> filter(all, zip(list_one, list_two))
[('a', 'ok'), ('b', 'good'), ('d', 'great'), ('g', 'amazing'), ('h', 'terrible'), ('i', 'not bad')]
You could do it by scrolling through the indices of the two lists because they are the same size, try this...
for x in range(len(list_two)):
if list_two[x] == None:
pass
else:
e = (list_two[x],list_one[x])
final_list_of_tuples.append(e)
print(final_list_of_tuples)
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