Xslt template. xsl if not working
Question
I'm trying to create 2 tables one that display when is greater and one for when is less. The first table is working fine but creating a second table is not working.
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
<xsl:output method="html" indent="yes"/>
<!-- template that is use for root-->
<xsl:template match="/">
<html>
<!--Displays a heading above the list of movie title-->
<head>
<title> Movies</title>
</head>
<body>
<!--Displays a heading above the list of movie title-->
<h1 align="center">
<font color="red" size="10">Movies Listing</font>
</h1>
<!-- Creates the table-->
<table style="color:blue;" bgcolor="gray" cellpadding="5" border="1" align="center">
<tr style="font-family:arial; color:blue;">
<td>Movie ID</td>
<td>Title</td>
<td>Director</td>
<td> Movie Year</td>
</tr>
<!-- apply template stament to use the template for movie-->
<xsl:apply-templates select="movies/movie">
<xsl:sort select="title" order="ascending"></xsl:sort>
</xsl:apply-templates>
</table>
</body>
</html>
</xsl:template>
<!-- template for each movie element-->
<xsl:template match="movie">
<xsl:if test="year<2005">
<tr>
<td>
<xsl:apply-templates select="@id"/>
</td>
<td>
<xsl:apply-templates select="title"/>
</td>
<td>
<xsl:apply-templates select="Director"/>
</td>
<td>
<xsl:apply-templates select="year"/>
</td>
</tr>
</xsl:if>
<xsl:apply-templates select="year">
</xsl:template>
<xsl:template match="year">
<table>
<tr style="font-family:arial; color:blue;">
<td>Movie ID</td>
<td>Title</td>
<td>Director</td>
<td> Movie Year</td>
</tr>
<xsl:if test="year>=2005">
<tr>
<td>
<xsl:apply-templates select="@id"/>
</td>
<td>
<xsl:apply-templates select="title"/>
</td>
<td>
<xsl:apply-templates select="Director"/>
</td>
<td>
<xsl:apply-templates select="year"/>
</td>
</tr>
</xsl:if>
</table>
</xsl:template>
<!-- template for color and font use for text in each element-->
<xsl:template match="@id">
<span style="font-family:arial; color:blue;">
<xsl:value-of select="."/>
</span>
</xsl:template>
<xsl:template match="title">
<span style="font-family:arial; color:blue;">
<xsl:value-of select="."/>
</span>
</xsl:template>
<xsl:template match="Director">
<span style="font-family:arial; color:blue;">
<xsl:value-of select="."/>
</span>
</xsl:template>
<xsl:template match="year">
<span style="font-family:arial; color:blue;">
<xsl:value-of select="."/>
</span>
</xsl:template>
</xsl:stylesheet>
I created an if statement but is only working for the first table. Can I do a choose statement to create both table and test the element?
1 answers
solution1
2 2017-10-30 07:39:02
In the match="year" template, you use the condition test="year>=2005" . A bare name year in an XPath expression means ./child::year , that is, select the year children of the context node. But the context node is a year element, and I doubt it has a child called year . Use test=".>=2005" .
I suspect that the year element doesn't have children called title or Director either. I suspect what you really want is to have one template rule with match="movie[year>=2005]" and one with match="movie[year<2005]" .
But since you haven't shown your input or expected output, it's hard to know exactly what you are trying to achieve.
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