I am trying to create multiple forms which have two buttons, each will submit the form to different script, one via ajax and second one will just submit the form.
<?php foreach($objects as $object) : ?>
<div class="card-body">
<form id="edit-form" action="#" method="POST">
<input name="subject" value="<?=$object['subject']?>" type="text" id="title" class="input-xxlarge">
<textarea id="content" name="content" rows="25"><?=$object['content']?></textarea>
<button type="button" id="send-button" class="btn btn-primary">Send</button>
<input type="submit" id="submit-button" value="Submit"/>
</form>
</div>
<?php endforeach; ?>
First I am trying to get the current form, but I have problem with that. console.log
shows something only on the first form, if I click on the buttons from other forms then It will do nothing.
$('#send-button').on('click', function(e) {
e.defaultPrevented;
$form = $(this);
$url = $form.attr('action');
$data = $form.serialize(); console.log($form);
console.log($url);
});
Is it because my button has same ID for every form ?
You shouln't use ID's multiple times on the same page. Try to use a class for that case. Also as stated in the comments use e.preventDefault();
to stop the event.
$(this)
will result in the #send-button
beeing targeted. To access the form you need to find the closest form
element like this:
$form = $(this).closest('form');
html:
<form method="POST" action="#">
<input type="text">
<button type="button">send</button>
<input type="submit" value="submit" />
</form>
<form method="POST" action="#">
<input type="text">
<button type="button">send</button>
<input type="submit" value="submit" />
</form>
js:
$("form").each(function() {
var form = this;
$(form).find('button').on('click', function(e) {
e.preventDefault();
console.log(form);
console.log(this);
})
});
this will add events on every form you have on your page, button
will submit form via script and submit
will just submit it. also here's a fiddle to play with
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