I have a parent UIView inside a UIViewController. This parent UIView is put under segmented control such that when a different index is selected, this parent view brings to front the according added subviews (eg currentViewController().view).
var parentView: UIView!
var currentView: UIView!
override func viewDidLoad() {
currentView = currentViewController().view
parentUIView.addSubview(currentView)
parentUIView.bringSubview(currentView)
}
There is a UITableView inside currentViewController. Since the controller is built under xib, I register the cells inside the currentViewController. (example code is the following)
import UIKit
class currentViewController: UIViewController, UITableViewDelegate, UITableViewDataSource {
@IBOutlet var stockInfo: UITableView!
override func viewDidLoad() {
super.viewDidLoad()
stockInfo.delegate = self
stockInfo.dataSource = self
stockInfo.register(UITableViewCell.self, forCellReuseIdentifier: "something")
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return 2
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = stockInfo.dequeueReusableCell(withIdentifier: "something", for: indexPath) as! UITableViewCell
cell.textLabel?.text = "testing DEFAULT"
return cell
}
The code is very simple and straight forward. When segmented control is selected, I check the index and bring this view to the front. The above code is just an example. I have other views too.
Unfortunately, my hard-coded cells (for debugging convenience) don't even show up for more than a second. They appear when the view is first loaded but then disappear in a second without any user actions. I suppose they are deallocated? Or is there any reason that I am unaware of? Can someone help? I have been stuck on it for hours.
let me add smth, i have wasted whole day to figure it out. my table view cells were disappearing after reloadData(). the solution was -> to unhide cells in prepareForReuse(), prepareForReuse() is used inside cell class itself.
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