retrieve and display data using $user_id
Question
My aim is to display a clip of a user's bio data from the users table in mysql database whenever a user makes a post to be diplayed on a feeds-view.php page just as is obtainable in facebbok and twitter using the $user_id passed along with the message to the posts table in mysql db when a user makes a post. So I'm trying to use the $user_id of the user(who made the post) to query their bio data from the users table in the database. I'm looking to display an image and a few other info such as name, phonenumber etc. and also to create a kind of loop so subsequent posts assume same template or structure. The code I devised below failed. Please I need help on this.
secondly, I attempted using session variables to transfer data from users table to posts table as a way to obtain bio data of a signed in user to be displayed when a post is made but I was stymied at transfering a session variable containing an image(jpeg) example is $image = $_SESSION['image']; as I tried to transfer the value to posts table to be displayed in feeds-view page, it says "Error You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' id='W5M0MpCehiHzreSzNTczkc9d'?>"
Target: Is to display bio data (ie image, name etc) of the user who makes a post or whose post is being displayed on the feeds-view.php page and also to create a kind of loop so subsequent posts assume same template or structure.
<?php
session_start();
if(!isset($_SESSION['username'])){
header('location:landing page.php');
include_once('server.php');
//include_once('server2.php');
function load_user_objects($user_id){
$query = "select * from clientcompany where id = '$user_id'";
$result = mysqli_query($conn,$sql);
if (!$result){
return "no user found";
}
return $result[0];
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title>W3.CSS</title>
<meta name="viewport" content="width=device-width, initial-scale=1">
</head>
<body>
<div>
<?php
include_once('server.php');
$sql = "SELECT * FROM post ORDER BY DESC";
$result = mysqli_query($conn,$sql);
function load_user_objects($user_id){
$query = "select * from users where id = '$user_id'";
$result = mysqli_query($conn,$sql);
if (!$result){
return "no user found";
}
return $result[0];
}
function do_news_feed($user_id){
$status_objects = $this->get_status_objects($user_id);
foreach($status_objects as $status){?>
<div>
<?php $users = $this->load_user_objects($status->user_id);?>
<?php //this attempts to display foto of a user who makes a post. Image accessed from users table.
include_once('server.php');
function getimage($user_id){
$query = "SELECT image FROM users WHERE id = '$user_id'";
$result = mysqli_query($conn,$query);
while($row = mysqli_fetch_array($result))
{
echo $users->'<img src="data:image/jpeg; base64,'.base64_encode($row['image']).'"class="w3-circle" alt="userfoto"
style="width:100px; height: 100px; margin-top: 70px; margin-left: 20px">';
}
}
?>
<?php // this attempts to access the users table to display data using the load_user_objects function
echo $users->name;
?>
<?php
echo $users->location[posts table][1];
?>
<?php // this attempts to access the posts table to display data.
echo $status->title;
?>
<?php
echo $status->message;
?>
</div>
<?php
}
}
?>
</div>
</body>
</html>
1 answers
solution1
0 2017-12-26 01:56:43
Probably you get that error on MariaDB because you have this line wrong (you send MariaDB to order the rows by an empty field):
$sql = "SELECT * FROM post ORDER BY DESC";
Reading your question, I supposed you want to order all the rows by "id" field so you must replace the wrong line for this one:
$sql = "SELECT * FROM post ORDER BY id DESC";
That way MariaDB won't throw that error and you can keep developing your idea
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.