How to set a go to a directory and execute a command in a batch file?

Question

During the deployment of the windows application that I make, I have to run a few commands in the CommandPrompt to update the database. I was thinking of making a batch file to automate this process so that the user can update the database just by double-clicking the batch file. Following is the screenshot for the same.

I want my batch file to go to the current directory where the .bat file is located. Then i want to execute the DBUpdater exe file against the config file.

I am new to batch programming so anything informative will help a lot. Thank you.

Answer 1

Create a batch file named DBUpdater.bat in any directory of your choice with the below script:

@ECHO OFF
setlocal
cd /d %~dp0
DBUpdater.v15.2.exe OfficeManagement.win.exe.config

This assumes that the OfficeManagement.win.exe.config file exists in the same directory as batch file and that DBUpdater.v15.2.exe is recognized as a global command.