package impatient.mapsAndTups.objects
abstract class UnitConversion {
def convert[T](x: T): T
}
class Inches2Centimeters extends UnitConversion {
override def convert[Int](x: Int): Int = x * 100
}
object Conversions extends App {
val c = new Inches2Centimeters()
println(c.convert(15))
}
I'm not understanding why the preceding code is not compiling. I'm getting the error:
Error:(9, 46) value * is not a member of type parameter Int
override def convert[Int](x: Int): Int = x * 100
What can I do to fix this?
You have "shadowed" the standard type Int with your own Int within the scope of your method convert . That's because you defined convert to work with a parametric type whose name is Int and which will be defined by callers (and type inference).
One way to fix your code is the following, although I wouldn't do it this way myself.
package impatient.mapsAndTups.objects
abstract class UnitConversion {
def convert[T](x: T): T
}
class Inches2Centimeters extends UnitConversion {
def convert[T](x: T): T = x match {
case t: Int => (t * 100).asInstanceOf[T]
}
}
object Conversions extends App {
val c = new Inches2Centimeters()
println(c.convert(15))
}
Note also that you don't need to override convert in your concrete class.
Instead, I would use the "typeclass" Numeric as follows:
package impatient.mapsAndTups.objects
abstract class UnitConversion {
def convert[T: Numeric](x: T): T
}
class Inches2Centimeters extends UnitConversion {
def convert[T: Numeric](x: T): T = {
val n = implicitly[Numeric[T]]
n.times(n.fromInt(100), x)
}
}
object Conversions extends App {
val c = new Inches2Centimeters()
println(c.convert(15))
}
I think, what you want is to declare the type parameter at the class level, not function:
abstract class UnitConversion[T] {
def convert(x: T): T
}
class Inches2Centimeters extends UnitConversion[Int] {
override def convert(x: Int): Int = x * 100 // this multiplier is wrong :)
}
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