I have some html divs that are generated using jinja2 with this:
{% for student in students %}
<div class="item" id="{{ student.id }}_div">
<div class="right floated content">
<div class="negative ui button compact remove_from_class" id="{{ student.id }}">Remove from Class</div>
</div>
<i class="large user icon middle aligned icon"></i>
<div class="content">
<div class="header">
<h3><u>{{ student.get_full_name }}</u></h3>
</div>
<div class="description">{{ student.email }}</div>
</div>
</div>
{% endfor %}
This is the script I have for it which gets the parent divs id, and then tries to remove it using .remove().
$(".remove_from_class").each(function () {
$(this).on("click", function () {
var id = this.id;
var url = window.location.pathname.split('/');
var set_id = url.pop() || url.pop()
$.ajax({
method: 'POST',
url: '/ajax/delete_from_class/',
data: {
'id': id,
'set_id': set_id,
},
dataType: 'json',
success: function (data) {
if (data.success == true) {
var div_id = id + "_div";
var parent_div = $(div_id);
parent_div.remove();
} else {
alert("Student wasn't removed!");
}
}
})
})
})
However the div isnt being removed, even though the success popup appears.
Thanks for any help!
You need to use #
to use id
as a selector.
var div_id = "#"+id + "_div"; // Use # here
var parent_div = $(div_id);
parent_div.remove();
Or the better approach I would suggest here is to store div
inside .click
in some variable and then later use that.
$(".remove_from_class").each(function () {
$(this).on("click", function () {
var $parentDiv = $(this).closest(".item"); // Save it here
var id = this.id;
var url = window.location.pathname.split('/');
var set_id = url.pop() || url.pop()
$.ajax({
method: 'POST',
url: '/ajax/delete_from_class/',
data: {
'id': id,
'set_id': set_id,
},
dataType: 'json',
success: function (data) {
if (data.success == true) {
$parentDiv.remove(); // And remvoe it here
} else {
alert("Student wasn't removed!");
}
}
})
})
})
请尝试这样
$('#'+ id +'_div').remove();
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.