I implemented the following groupby statement in my code. The purpose of the code below is to provide the minimum date from the "DTIN" column by unique EVENTID.
df_EVENT5_future_2 = df_EVENT5_future.groupby('EVENTID').agg({'DTIN': [np.min]})
df_EVENT5_future_3 = df_EVENT5_future_2.reset_index()
The output table is follows:
EVENTID DTIN
amin
A 1/3/2019
B 1/19/2019
C 2/10/2019
I would like the table to output like this. I don't want the amin to be in the column header.
EVENTID DTIN
A 1/3/2019
B 1/19/2019
C 2/10/2019
Any help is greatly appreciated.
This is as per @Wen's suggestion. You don't need to use agg
for this. Simply use groupby.min()
and set as_index=False
:
result = df.groupby('EVENTID', as_index=False)['DTIN'].min()
Please do not upvote or accept this answer, as this is a duplicate.
Example
df = pd.DataFrame({'DTIN': {0: 4, 1: 3, 2: 9, 3: 1, 4: 2, 5: 5, 6: 6, 7: 5},
'EVENTID': {0: 'A', 1: 'A', 2: 'A', 3: 'B', 4: 'C', 5: 'B', 6: 'B', 7: 'C'}})
result = df.groupby('EVENTID', as_index=False)['DTIN'].min()
# EVENTID DTIN
# 0 A 3
# 1 B 1
# 2 C 2
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