override jquery hide() using inline css

Question

HTML

<div class="dep-adm-inp" <?php if(!empty($adm_f) || $adm_f != "") echo "style='display:block'"; ?> id="fees-inp">
    <label>Admission Fees(<i class="fa fa-inr"></i>)</label>
    <div class="input-group">
        <span class="input-group-addon remove-inp"><i class="fa fa-close"></i></span>
        <input type="text" class="form-control expected" value="<?php if(!empty($adm_f)) echo $adm_f; ?>" placeholder="Amount Expected">
        <input type="text" class="form-control paid" value="<?php if(!empty($adm_f)) echo $adm_f; ?>" placeholder="Paid Amount">
    </div>
</div>

Javascript

$(".dep-adm-inp").hide();

the div is hidden when page loads but if the php variable is not empty then i want to show the div when.

Answer 1

set the class variable dep-adm-inp as hidden by default in css. If the variable $adm_f is not empty, set style='display:block;' . With this logic you don't need to call the statement $(".dep-adm-inp").hide(); in your javascript. This way the div will be shown only if the variable $adm_f is not empty.

Answer 2

.hide() method sets display:none; on your element. You can override it by setting display: block!important; (or whatever your display property is) in CSS:

 setTimeout(() => { $('.item').hide(); }, 2000); 

 .container { display: flex; } .item { width: 200px; height: 100px; background-color: darkgoldenrod; margin: 10px; } /* This makes .item visible even after .hide() */ .item-visible { display: block!important; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="container"> <div class="item item-visible">Will be visible</div> <div class="item">Will be hidden</div> </div>