js and am using react-router-dom
.
Say I have 2 files - 1. dashboard.js
file
import React, { Component } from 'react';
import {Switch, Route, Link} from 'react-router-dom';
import WYSIWYG from './editor/wysiwyg';
export default class Dashboard extends Component{
render(){
return(
<div className="wrapper">
<Switch>
<Route exact path="/wysiwyg" component={WYSIWYG}/>
</Switch>
<ul id="DASHBOARD-MENU">
<li><Link to={{ pathname: '/wysiwyg'}}>WYSIWYG</Link></li>
</ul>
</div>
);
}
}
Note the
ul
withid="DASHBOARD-MENU"
above
2nd - wysiwyg.js
file
import React, { Component } from 'react';
export default class Wysiwyg extends Component{
render(){
return(
<div id="WYSIWYG-CONTAINER">
</div>
);
}
}
Note the
div
withid="WYSIWYG-CONTAINER"
in the above snippet
After redirection to WYSIWYG
container from my dashboard
, I can still see the - <ul id="DASHBOARD-MENU" ..
rendered below the <div id="WYSIWYG-CONTAINER ..
.
What I understood - is the component WYSIWYG
is rendered replacing <Route
declared in my dashboard.js
file.
I don't want the "DASHBOARD-MENU"
element to render in my "WYSIWYG"
page.
Is it possible?
The desired behavior can be obtained by considering both as different routes, and hence rendering only one of them depending on the path:
import React, { Component } from 'react';
import {Switch, Route, Link} from 'react-router-dom';
import WYSIWYG from './editor/wysiwyg';
const Dashboard = () => (
<ul id="DASHBOARD-MENU">
<li><Link to={{ pathname: '/wysiwyg'}}>WYSIWYG</Link></li>
</ul>
);
export default class Dashboard extends Component{
render(){
return(
<div className="wrapper">
<Switch>
<Route exact path="/" component={Dashboard} />
<Route exact path="/wysiwyg" component={WYSIWYG}/>
</Switch>
</div>
);
}
}
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