I am trying trying to find the number of circular primes from a given limit. The prime(x) will return whether a number is a prime or not. The rotations() will return a list of rotated numbers. Lastly, prime_count() will output the total amount of circular primes based on the given limit. Both prime() and rotations() gave me the correct output; however, prime_count() is not incrementing like it should. Any ideas on what i did wrong?
def prime(number): #return true or false
return all(number% i for i in range(2,number))
def rotations(num): #rotating number and return list
list = []
m = str(num)
counter = 0
while counter < len(str(num)):
m=m[1:] + m[0]
list.append(int(m))
counter+=1
list1=sorted(list,key=int)
return list1
def prime_count(limit): #return numbers of circular primes from given limit
counter = 0
for i in range(1,limit+1):
a=rotations(i)
for j in a:
if j == prime(j):
counter+=1
return counter
print(prime_count(100))
There are a few problems with your code:
Your prime
function has a bug:
In [8]: prime(1) Out[8]: True
It erroneously returns True
for any number less than 2 due to range(2, n)
being empty and any([]) == True
.
prime_count
should be counting the total number of circular primes below limit
. prime(j)
returns a boolean, but you check j == prime(j)
, which can only be true if j
is zero or one, which definitely isn't what you want. Try creating an is_circular_prime
function that takes in an integer n
and returns whether or not the prime is circular. Then, prime_count
becomes easy to write.
This is the heart of the problem:
a=rotations(i)
for j in a:
if j == prime(j):
counter+=1
You're counting the wrong thing (eg 13 counts twice independent of 31 counting twice) and you're comparing the wrong thing (numbers against booleans.) The problem is simpler than you're making it. Rearranging your code:
def prime(number):
return number > 1 and all(number % i != 0 for i in range(2, number))
def rotations(num):
rotated = []
m = str(num)
for _ in m:
rotated.append(int(m))
m = m[1:] + m[0]
return rotated
def prime_count(limit):
counter = 0
for number in range(1, limit + 1):
if all(prime(rotation) for rotation in rotations(number)):
counter += 1
return counter
print(prime_count(100))
Note that you don't need to sort the rotations for this purpose. Also list
, or any other Python built-in function, is a bad name for a variable.
Problem may be here:
for i in range(1,limit+1):
a=rotations(i)
for j in a:
if j == prime(j): # Prime will return True or False, comapring with J will cause it False ,except when J = 1
counter+=1
Changing it to prime(j)
for i in range(2,number//2):
if(number%i==0):
return False
return True
def rotations(num):
count=0
rotation_lst=[]
num=str(num)
while(count<len(num)):
num=num[1:]+num[0]
count+=1
rotation_lst.append(int(num))
rotation_lst1=sorted(rotation_lst,key=int)
return rotation_lst1
def get_circular_prime_count(limit):
count=0
for i in range(1,limit+1):
a=rotations(i)
for j in a:
if(check_prime(j)):
count+=1
return count
print(get_circular_prime_count(1000) ```
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