How to open a material design dialog from the code (.xaml.cs)?

Question

i'm coding a wpf application using material design

i've a DialogHost named dialog and i want to open and show its content from the code (.xaml.cs), in XAML the command is Command="{x:Static materialDesign:DialogHost.OpenDialogCommand}" but i sought in DialogHost properties and methods and i didn't find anything...

Answer 1

From: https://github.com/ButchersBoy/MaterialDesignInXamlToolkit/wiki/Dialogs#dialoghostshow

var result = await DialogHost.Show(view, "RootDialog", ClosingEventHandler);

If you'd like a concrete example, check out the demo source:

https://github.com/ButchersBoy/MaterialDesignInXamlToolkit/blob/2740f14a814896d42032ae0013b765a8a0ec04c3/MainDemo.Wpf/Domain/DialogsViewModel.cs#L36

Answer 2

你可以简单地使用这个：

view.IsOpen = true;

Answer 3

You can set a Name to your DialogHost like: <materialDesign:DialogHost x:Name="MyDialogHost"> .

And then in your XAML.CS file you can use the MyDialogHost.ShowDialog(...) method to show its content like:

private void MyButton_Click(object sender, RoutedEventArgs e)
{
      MyDialogHost.ShowDialog(MyDialogHost.DialogContent);
}

Answer 4

In your ViewModel where you host a Dialog, you can simply add these lines:

var dialog = DialogHost.OpenDialogCommand;
dialog.Execute(null, null);