How can I render a partial view from within a layout file?
Question
To add some context, I learned that within a view folder you can just create a file and add a partial with "_partialname", such as "_login". on my index.html.erb file or any other file I would usually place a:
<%= render "login" %>
Which is what I did for the layouts folder, but it is not working.
Below is a snippet of my file /views/layouts/application.html.erb . Within the same layouts folder, I created a _footer.html.erb , which I want all my views to have, but when I try the following, it gives me an error:
</head>
<body>
<%= yield %>
<%= render "footer" %>
</body>
</html>
Adding error message:
Missing partial static/_footer, application/_footer with {:locale=>[:en], :formats=>[:html], :variants=>[], :handlers=>[:raw, :erb, :html, :builder, :ruby, :coffee, :jbuilder]}.
Searched in:
* "/Users/rogerperez/DevProjects/Property-Pal/app/views"
Update: added context on for the reason on my question
3 answers
solution1
1 ACCPTED 2018-05-11 01:12:59
I believe your path is wrong in this case. Change the code to
<%= render 'layouts/footer' %>
solution2
1 2018-05-11 06:01:42
该代码将从app / views / layouts / _footer.html.erb中提取部分代码。
<%= render :partial => "layouts/footer" %>
solution3
0 2018-05-11 02:01:42
如果_footer.hml.erb在layouts文件夹中，则可以通过以下方式在../views/layouts/application.html.erb中进行渲染：
<%= render 'layouts/footer' %>
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