I have a cumulative distribution function from a standard normal distribution and I have a given y value, which should be 0.95
dist <- function(x) pnorm(x,0,1)
How can I solve the equation 0.95 = dist(x)
for x?
You can use the uniroot function as follows:
dist <- function(x) pnorm(x,0,1) - 0.95
uniroot(dist, interval = c(-1,4))
which would give you the same answer as qnorm(0.95,0,1).
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