I'm looking for how to get the url of ForeignKey related model in metadata(OPTIONS).
Models:
Class Country(models.Model):
pass
Class City(models.Model):
country = ForeignKey(Country)
I wish the "choices_url" below can be showed on the OPTIONS:
City's API (OPTIONS)
"actions": {
"POST": {
"country": {
"type": "related",
"required": true,
"read_only": false,
"label": "Country",
"choices_url": "http://example.com/api/country/"
Thanks.
I checked, it reverse to a URL from the "view_name" and the view_name of the field is "{basename}-detail". Override the SimpleMetadata with the following class and set to default metadata class in settings.py. The problem has been solved. The "choices_url" is displayed the list_view url.
import re
def get_view_name(view_name: str, view_type: str) -> str:
if view_type in ['list', 'detail']:
return re.sub('(.*)-[^.]*', f'\\1-{view_type}', view_name)
raise ValueError(
f"Wrong view_type. It should be either 'list' or 'detail'. "
f'<:param view_type>: {view_type}')
class RestMetadata(SimpleMetadata):
def get_field_info(self, field):
field_info = super().get_field_info(field)
if (not field_info.get('read_only') and
hasattr(field, 'choices')):
if isinstance(field, serializers.HyperlinkedRelatedField):
view_name = get_view_name(field.view_name, 'list')
field_info['choices_url'] = field.reverse(view_name, request=field.parent.context['request'])
elif (
isinstance(field, serializers.ManyRelatedField)
and isinstance(field.child_relation, serializers.ManyRelatedField)):
field_child = field.child_relation
view_name = get_view_name(field_child.view_name, 'list')
field_info['choices_url'] = field_child.reverse(view_name, request=field.parent.context['request'])
return field_info
{Project}/settings.py
REST_FRAMEWORK = {
'DEFAULT_METADATA_CLASS': '{Path-of-RestMetadata}.RestMetadata'
}
Thanks.
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