I have dropdown. When I select any value and click on confirm, Below it should print the selected value and also the selected value should be shown in the dropdown. How can I achieve this.
<!DOCTYPE html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<!--Links related to dropdown-->
<link href="http://localhost/performance/Test/css/fselect.css" rel="stylesheet">
<script src="http://localhost/performance/Test/js/fSelect.js"></script>
<script>
(function($) {
$(function() {
$('#project_name').fSelect();
});
})(jQuery);
</script>
</head>
<body>
<?php
$projects = array('Trial','Test','Birds','Animals');
?>
<div class="container">
<div><center><b>This test will be created in the selected project:</b></center></div><br>
<div class="create_test">
<form action="#" method="post">
<div style="margin-left:2cm;">
<select name="project_name" id="project_name" >
<?php
for($i=0; $i<count($projects); $i++) {
echo "<option value='".$projects[$i]."'>".$projects[$i]."</option>";
}
?>
</select>
<input type="submit" style="margin-left:3.5cm; width:140px;" name="submit" id="comfirm" class="btn btn-success" value="Confirm" />
</div>
</form>
</div>
</div>
</body>
</html>
<?php
/** Store selected in a varaible in php */
$selected = 'trial';// Suppose get the value from db here
for($i=0; $i<count($projects); $i++) {
echo "<option value='".$projects[$i]."' selected='".$project[$i] == $selected."'>".$projects[$i]."</option>";
}
?>
So adding the selected='true' will be used as value for the select tag
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