Description
From the sample code below, the FlatList returns n-number of TextInput, when a value is entered on a particular TextInput it keeps re-rendering every other TextInput.
Sample Code
<FlatList
...........
renderItem ={this.renderItem}
/>
renderItem=(item)=>{
<Text>{item.name}</Text>
<TextInput
.........
onChangeText ={(text)=>this.setState({text})}
value={this. state.text}
/>
}
Solution
I have tried to assign a key to the TextInput but don't know how to go avout it
Update : Added Complete Example
You need to maintain textinputs state as an array to store the values for each textinput
import React, { Component } from 'react';
import {
View,
Text,
FlatList,
TouchableOpacity,
TextInput,
} from 'react-native';
export class Demo extends Component {
state = {
textInputs: [],
};
render() {
return (
<View style={{ flex: 1, marginTop: 20 }}>
<FlatList
style={{ flex: 1 }}
data={[1, 2, 3, 4, 5]}
renderItem={({ item, index }) => {
return (
<View
style={{
height: 100,
backgroundColor: '#F0F0F0',
width: 300,
alignSelf: 'center',
margin: 10,
}}
>
<TextInput
style={{
flex: 1,
backgroundColor: '#C0C0C0',
}}
onChangeText={text => {
let { textInputs } = this.state;
textInputs[index] = text;
this.setState({
textInputs,
});
}}
value={this.state.textInputs[index]}
/>
<TouchableOpacity
style={{
backgroundColor: 'red',
flex: 1,
alignItems: 'center',
justifyContent: 'center',
}}
onPress={() => {
let { textInputs } = this.state;
textInputs[index] = '';
this.setState({
textInputs,
});
}}
>
<Text> Clear</Text>
</TouchableOpacity>
</View>
);
}}
/>
</View>
);
}
}
Just remove value
attribute from your TextInput
, but this is not the solution as the value is stores into single state only, so if you want to get value of multiple textinputs you have to create rowrender and array of states
<TextInput
.........
onChangeText ={(text)=>this.setState({text})}
//value={this. state.text}
/>
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.