How can I convert a gregorian time vector into datetime in Python?

Question

I have a vector of time in Gregorian type. I want to convert it in the common format of dates with year, month, day, hour, minute and seconds.

I tried this:

from datetime import datetime

datetime.fromordinal(736364.94)

It returns always something only with the information of year, month and day. Like this:

datetime.datetime(2017, 2, 4, 0, 0)

I was expecting a date with hours, minutes and seconds information

Answer 1

I think the ordinal is for days only, but assuming the decimal is representative of the fraction of the day you can use this.

import datetime
datetime.fromordinal(int(736364.94))+datetime.timedelta(days=736364.94%1)