Node/Webpack/javascript es6 - Add a condition on a require inside Object.Assign()

Question

I have a module that sets the language by requiring the right index.{i18n}.js

The code below works fine for pathes (urls) with /fr/, /en/, /es/...

module.exports = function (locals) {
  var route = global.RoutesPages.routes.find(r => r.url == locals.path);
  const language = locals.path.split('/')[1]; 
  return Promise.resolve(    
      locals.template(
      Object.assign(
        {},
        {           
          title:        route.title,
          type:         route.type
        },

       require(`../../i18n-build/index.${language}.js`)

      )
    )
  )

};

So it requires for example.com/fr/cool the file i18n-build/index.fr.js , and it requires for example.com/en/cool the file i18n-build/index.en.js

The issue is I have a case where the url is example.com/global and so the require tells me it can't find the right file because it tries to require for example.com/global/foo the file i18n-build/index.global.js which is to be expected because I don't this file and don't want to. Indeed for users accessing example.com/global, I want to use the i18n-build/index.en.js with english as a "global" user default

I tried to use a condition inside the require but then the build fails:

module.exports = function (locals) {
  var route = global.RoutesPages.routes.find(r => r.url == locals.path);
  const language = locals.path.split('/')[1];
  function isCountry() {
    //detect if language in uri is "global", 
    //i.e not a specific country
    if (language !== "global" ) {
      return true;
    }
  }

  return Promise.resolve(    
      locals.template(
      Object.assign(
        {},
        { 
          title:        route.title,
          type:         route.type
        },

        require( isCountry ? `../i18n-build/index.${language}.js` : `../i18n-build/index.en.js` )        

      )
    )
  )

};

It seems to break what was working before when webpack is building the files for one url with /fr/, I get the error:

Cannot find module '../i18n-build/index.fr.js'

And the whole build fails.

I think how I write it is incorrect but i don't know how to apply a condition which basically goes like this:

If (isCountry), require ../i18n-build/index.${language}.js , else require ../i18n-build/index.en.js

EDIT

After some comments asking me to test various requires here are the results on the build :

• require( ../../i18n-build/index.${language}.js ) => build works

• require( ../../i18n-build/index.fr.js ) => build works

• require( isCountry ? ../i18n-build/index.${language}.js : ../i18n-build/index.en.js ) => build fails

• require( isCountry ? ../i18n-build/index.fr.js : ../i18n-build/index.en.js ) => build fails

• require( isCountry ? ../../i18n-build/index.fr.js : ../../i18n-build/index.en.js ) => build works!!

• require( isCountry ? ../../i18n-build/index.${language}.js : ../../i18n-build/index.en.js ) => build fails

The last one really suggest the issue is about how to properly create a condition on a require because both files do exist, i am not even using a variable ($language) inside them

Answer 1

Kindly change your language assignment line by this:

const language = locals.path.split('/')[1] == 'global' ? 'en' : locals.path.split('/')[1];

And then use the 1st code require .

require(`../../i18n-build/index.${language}.js`)

Answer 2

因此错误一定是拼写错误，请尝试在条件中添加../ more：

require( isCountry ?`../../i18n-build/index.${language}.js`:`../../i18n-build/index.en.js`)