I have a dataframe like this
geo 2001 2002
Spain 21 23
Germany 34 50
Italy 57 89
France 19 13
As the names of 2nd an 3rd column are considered as number I'm not able to get a bar chart wth ggplot2. Is there any solution to set the column names to be considered as text?
data
pivot_dat <- read.table(text="geo 2001 2002
Spain 21 23
Germany 34 50
Italy 57 89
France 19 13",strin=F,h=T)
pivot_dat <- setNames(pivot_dat,c("geo","2001","2002"))
Here's how to do it :
library(ggplot2)
ggplot(pivot_dat, aes(x = geo, y = `2002`)) + geom_col()+ coord_flip()
by using ticks instead of quotes/double quotes you make sure you pass a name to the function and not a string.
If you use quotes, ggplot
will convert this character value to a factor and recycle it, so all bars will have the same length of 1
, and a label of value "2002"
.
Note 1 :
You might want to learn the difference between geom_col
and geom_bar
:
?ggplot2::geom_bar
In short geom_col
is geom_bar
with stat = "identity"
, which is what you want here since you want to show on your plot the raw values from your table.
Note 2 :
aes_string
can be used to give string instead of names but here it doesn't work as "2002"
is evaluated as a number :
ggplot(pivot_dat, aes_string(x = "geo", y = "2002")) +
geom_col()+ coord_flip() # incorrect output
ggplot(pivot_dat, aes_string(x = "geo", y = "`2002`")) +
geom_col()+ coord_flip() # correct output
Without an example to see exactly what your problem is, and what you want, it is hard to give you a perfect answer. But here's the thing.
You can do a geom_bar with numeric data. There are 3 possible ways I see that you could have problems (but I may not be able to guess every way.
First, let's set up the r for plotting.
library(readr)
library(ggplot2)
test <- read_csv("geo,2001,2002
Spain,21,23
Germany,34,50
Italy,57,89
France,19,13")
Next, let's make the first mistake...incorrectly calling the column name. In the next example I will tell ggplot to make a bar of the number 2001. Not the column 2001
! r has to guess whether we mean 2001 or whether we mean the object 2001
. By default it always picks the number instead of the column.
ggplot(test) +
geom_bar(aes(x=2001))
Ok, that just gives you a bar at 2001...because you gave it a single number input instead of a column. Let's fix that. Use the right facing quotes `` to identify the column name 2001
instead of the number 2001.
ggplot(test) +
geom_bar(aes(x=`2001`))
This creates a perfectly workable bar chart. But maybe you don't want the spaces? That's the only possible reason you would use text instead of a number. But you want text so I'm going to show you how to use as.factor
to do something similar (and more powerful).
ggplot(test) +
geom_bar(aes(x=as.factor(`2001`)))
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