I have this problem understand this code in the react tutorial page https://reactjs.org/tutorial/tutorial.html#declaring-a-winner
function calculateWinner(squares) {
const lines = [
[0, 1, 2],
[3, 4, 5],
[6, 7, 8],
[0, 3, 6],
[1, 4, 7],
[2, 5, 8],
[0, 4, 8],
[2, 4, 6],
];
for (let i = 0; i < lines.length; i++) {
const [a, b, c] = lines[i];
if (squares[a] && squares[a] === squares[b] && squares[a] === squares[c]) {
return squares[a];
}
}
return null;
}
This particular line
if (squares[a] && squares[a] === squares[b] && squares[a] === squares[c]) {
I don't understand why it can't be
if (squares[a] === squares[b] && squares[a] === squares[c]) {
What benefits are of having the extra squares[a] in the original code?
If you don't set the squares[a]
in the begin of if
condition, you can get the js error if squares[a]
is not defined.
For simple, we have the condition like this:
if (a && a === b && a === c) {
it will check the a
variable first, if it not defined, the after will not execute.
It is checked if squares[a] is not null, undefined, 0, empty string '' and false, so that further checks of squares[a] would be possible. If squares[a] is null or undefined or false or 0 then the condition would return false and further checks won't be done due to "&&" condtion operator.
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