Maintaining names while flattening lists in R

Question

Below is some dummy data and code. I think I'm trying to do the exact opposite to this question.

After manipulating for a statistical test , I'm left with a very ugly looking list. When I unpack this list as per this method with unlist , the variable/country coding stored in names is totally lost.

I would like to have a data frame with countries as row names and categories as column names.

Any pointers would be much appreciated!

set.seed(1)

CVtest <- list()

for (i in c("AT","BE","DE")) { #For all countries

  # Test all categories together

  CVtest[[i]][["EveryCat"]] <-  sample(seq(0, 1, by=0.01), 1)

    for (j in c("All", "Sub", "Key", "Sel")) { # Test each category

      CVtest[[i]][[j]] <- sample(seq(0, 1, by=0.01), 1)
    }
}

Current output:

> class(CVtest)
[1] "list"
> CVtest

$`AT` EveryCat      All      Sub      Key      Sel 
    0.26     0.37     0.57     0.91     0.20 

$BE EveryCat      All      Sub      Key      Sel 
    0.90     0.95     0.66     0.63     0.06 

$DE EveryCat      All      Sub      Key      Sel 
    0.20     0.17     0.69     0.38     0.77

Desired output

> class(CVtest)
[1] "data.frame"
> CVtest
       EveryCat  All  Sub  Key  Sel
AT     0.26 0.37 0.57 0.91 0.20
BE     0.90 0.95 0.66 0.63 0.06
DE     0.20 0.17 0.69 0.38 0.77

Answer 1

Your question is still not clear (see my latest comment). I can only guess what you want. Could you try:

x <- purrr::transpose(CVtest)
y <- rlist::list.stack(x)
rownames(y) <- names(x)
y

Say me whether y is the desired output. Otherwise I will delete this answer and please clarify your question.