Default destructed function parameters in one object in JavaScript

Question

is there a possibility to access ALL destructed function parameters in one object?

So I have this function head:

function coolFunctionName({test1 = "foo", test2 = "bar"})

I want to access them in one object. arguments doesn't work, because there aren't stored the default parameters which doesn't have a value in function call.

Is there a good and clean way to do that?

EDIT: I don't need the destructed parameters. I just want to have all of them in one object.

Answer 1

Inspired from Faly's answer I think I've got the "cleanest" solution:

function coolFunctionName(options = {}){
    options = Object.assign({
        test1: "foo",
        test2: "bar
    }, options);
}

I have the parameter in one object and I have not to write multiple value names. I'm not happy about that because it's not in the function head but it's the best solution I've found.

Answer 2

To achieve expected result, use below option of setting default value inside function

 function coolFunctionName(x){ x.test1 = x.test1 || 'foo' x.test2 = x.test2 || 'bar' console.log(x) } let z ={} coolFunctionName(z); let y ={test1:"zzz", test2:"yyy"} coolFunctionName(y); 

codepen- https://codepen.io/nagasai/pen/KxBmod?editors=1011

Answer 3

All you can do is:

function coolFunctionName({test1 = "foo", test2 = "bar"}) {
    let arguments = { test1, test2 };
    /* Do whatever you want with arguments */
}