How can you pass a parameter from an action to the layout in Symfony
Question
The global layout.php file contains the tags for each page:
<body>
<?php echo $sf_content ?>
</body>
But for all my inner HTML pages of the site, a class is applied to the body tag:
<body class="inner-page">
<?php echo $sf_content ?>
</body>
How can I pass in a class to the layout from different templates?
5 answers
solution1
4 ACCPTED 2009-05-10 02:57:49
in your layout.php
<body <?php if (!include_slot('body_id')): ?>id="default"<?php endif; ?>>
in your templates :
<?php slot('body_id') ?>id="bla"<?php end_slot(); ?>
or
<?php slot(
'body_id',
sprintf('id="%s"', $sf_params->get('module')))
?>
solution2
4 2009-05-10 02:57:54
Here is the solution I used with Symfony 1.2+
Use setSlot() in the action:
$this->getResponse()->setSlot('home_page', 'yes');
Then use get_slot() in the Layout:
<body class="<?php echo has_slot('home_page') ? 'home-page' : 'inner-page' ?>">
solution3
0 2016-08-19 09:53:53
sfConfig::set('name_here', $variableHere);
$variable = sfConfig::get('name_here');
I use this a lot. Use this anywhere on the code.
solution4
0 2009-05-10 02:47:41
In most MVC frameworks, you access variables in the layout the same way you access them in the view files.
So, if you did something like $this->view->my_data=10; in the control. You can access it in the layout by: echo $this->my_data.
This was pseudo code, adjust it to the symphony way.
solution5
0 2009-05-10 04:03:17
I'm 90% sure that you do this the same way you'd do it from a regular view file. So as long as you set the variable in the action, it should be accessible from the layout.php file.
In your action:
$this->body_class = "xxx";
In layout.php
<body class="<?php echo $body_class?>">
Be sure to run some checks to make sure $body_class is set.
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