Login with Facebook In rails App without gem in rails app

Question

I wanna create a login with facebook without using the gem. By using facebook-sdk i am getting autoResponse: accessToken and userID . Now I need to sign_up in my rails app on after success event FB.Login.

Please suggest how to achieve this?

Thanks

Answer 1

Create a table to store the details that you get from facebook. On sucessful facebook signin save them to that table and then create a user using those details keep an association like

facebook_details belongs to user
user has many facebook_details

Using those associations create a user

Answer 2

You could create a table called social_logins , and assuming you have users table, you can build a has_many association b/w them, like user has_many social_logins , and in the social_logins table you could have a type column, which would store facebook , in the near future, if you want to implement let's say login with twitter or google , you can make use of type column and every other information could be stored in social_logins table.

class User < Activerecord::Base
  has_many :social_logins
end

class SocialLogin < Activerecord::Base
  belongs_to :user
end

Make sure social_logins table contains type column, and other columns such as authToken , user_id and any other additioanl information you want related to social_login. You can also make use of additional data, such as first_name , last_name , and so on, and create a User (Sign up).

Steps you will have to do.

1. Click Login with Facebook .
2. Enter FB email and password .
3. On successful check, in rails check if the user with that email exists, if he does not, create the user and use the additional information you got in the response to sign up the user and log him into the application .
4. Next time, existing user clicks Login with Facebook , enters his email and password , check if the user exists in DB, he does, so log him into the application directly.
5. The sign up happens only the very first time he tries to Login using Facebook .