How do you escape try/catch hell in Javascript?

Question

Ok, I like(d) try/catch with await/async.

But what do I do with this.

I wanted to do this..

let a = await doAbc();
let b = await do123(a);

what it becomes instead is

let a, b;

try {
   a = await doAbc();
} catch(e) {
   a = await doZxc();
}

try { 
   b = await do123(a);
} catch (e) {
   console.log(e);
   return;
}

if (b.data == undefined) {
    return -1;
} else {
    return b;
}

At this point I'm regretting everything.

Answer 1

Remember that you can await any promise. So you could do:

let a = await doAbc().catch(doZxc); // or .catch(() => doZxc())
let b = await do123(a);

Or even

 let b = await doAbc().catch(doZxc).then(do123);

Together with the rest of your code:

try { 
  let b = await doAbc().catch(doZxc).then(do123);
  return b.data == undefined ? -1 : b;
} catch (e) {
   console.log(e);
   return;
}

Answer 2

If it's all in one logical function, you can group all your await in one try and then take action based on error.

let a
let b
try {
  a = await doAbc();
  b = await do123(a);
} catch (err) {
  // take appropriate action based on err
}

Answer 3

Create to function first return a and second using first function returned value to create b , somthing like this code

function firstCode(){
    try {
       a = await doAbc();
    } catch(e) {
       a = await doZxc();
      }
    return a;
}
function secondFunction(){
try { 
   b = await do123(firstFunction());
} catch (e) {
   console.log(e);
   return;
}
}