Mongoose find all except one in aggregate users

Question

        User.aggregate([{
            $lookup: {
                from: "boughtitems", // collection name in db
                localField: "username",
                foreignField: "username",
                as: "boughtitems"
            }
        }]).then((users) => { 

Can someone help me to write this code so that I can find all users except myself ? Every logged in users has it's own session so I can find them by ID like so: User.findById(req.session.userId)

Answer 1

You can use $ne aggregation operator

User.aggregate([
  { "$match": { "_id": { "$ne": mongoose.Types.ObjectId(yourLoggedInId) }}},
  { "$lookup": {
    "from": "boughtitems",
    "localField": "username"
    "foreignField": "username",
    "as": "boughtitems"
  }}
])