I have an output as
VAR FREQ
1 A 2
2 R 3
3 B 4
I want to show result as
A 2
R 3
B 4
Which means that i want to remove Column Names and Serial Number
The query i am using is
data.frame(sort(table(substr(read.csv('extra/name.csv')$value, 1, 1)),decreasing =TRUE))
Kindly help with some pointers
We can set dimnames
to NULL
assuming it is a matrix
as mentioned in the post
dimnames(m1) <- NULL
If we need to print
, this can be done with cat
as @Gregor showed
d1 <- as.data.frame(m1)
cat(do.call(paste, c(d1, collapse='\n')), '\n')
#A 2
#R 3
#B 4
m1 <- structure(c("A", "R", "B", "2", "3", "4"), .Dim = 3:2, .Dimnames = list(
c("1", "2", "3"), c("VAR", "FREQ")))
cat
can be used to print results to the console without the niceties added by print
.
dd = read.table(text = " VAR FREQ
1 A 2
2 R 3
3 B 4", header = T, stringsAsFactors = FALSE)
dd
# VAR FREQ
# 1 A 2
# 2 R 3
# 3 B 4
for(i in 1:nrow(dd)) cat(unlist(dd[i, ]), "\n")
# A 2
# R 3
# B 4
Note that if your data has factor
s, you will need to convert them to character
to print like this. No guarantees are made about how columns of other classes will print (eg, Date
class). You also lose the justification and rounding done automatically by print
.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.