I have two model 1 is category, 2nd is details and I want make a view where i can click on a category and the link should take me to the list only for the current category what i clicked. my models are given:
class FoodCategory(models.Model):
categoryname = models.CharField(max_length=100)
categorydetails = models.CharField(max_length=1000)
categoryimage = models.ImageField(default='cat_def.jpg',
upload_to='catimg')
class Meta:
verbose_name = 'Food Category'
def __str__(self):
return self.categoryname
class FoodDetails(models.Model):
fromcategory = models.ForeignKey(FoodCategory,
on_delete=models.CASCADE)
foodname = models.CharField(max_length=100)
fooddetails = models.CharField(max_length=1000)
foodimage = models.ImageField(default='food_def.jpg',
upload_to='fodimg')
armodel = models.CharField(default='andy.sfb', max_length=50)
additiondate = models.DateTimeField(default=timezone.now)
addedby = models.ForeignKey(User, on_delete=models.CASCADE)
class Meta:
verbose_name = 'Food Detail'
def __str__(self):
return self.fromcategory.categoryname + \
' - ' + self.foodname + \
' - ' + 'added by' + \
' - ' + self.addedby.username
def get_absolute_url(self):
return reverse('food-details', kwargs={'pk': self.pk})
views.py file:
from django.shortcuts import render
from food.models import FoodCategory, FoodDetails
from django.views.generic import ListView, DetailView
class FoodCategoryView(ListView):
model = FoodCategory
template_name = 'food/food-category.html'
context_object_name = 'food'
class FoodListView(ListView):
model = FoodDetails
template_name = 'food/food-list.html'
context_object_name = 'food'
ordering = ['-additiondate']
class FoodDetailsView(DetailView):
model = FoodDetails
template_name = 'food/FoodDetails_detail.html'
and my urls.py file also:
from django.urls import path, include
from . import views
from .views import FoodCategoryView, FoodListView, FoodDetailsView
# api url handler
urlpatterns = [
path('category/', FoodCategoryView.as_view(), name='food-
category'),
path('foodlist/', FoodListView.as_view(), name='food-list'),
path('foodlist/<int:pk>/', FoodDetailsView.as_view(),
name='food-details')
]
here is my all files and i just want know a specific way to get the current category based food details.
You can do this by defining get_queryset
on a listview.
class FoodDetailsByCategory(ListView):
def get_queryset(self):
return FoodDetails.objects.filter(fromcategory_id=self.kwargs['category_id'])
with a simple URL:
path('category/<int:category_id>', FoodDetailsByCategory.as_view(), name='food_details_by_category')
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