Is there a way to tell gulp-sass
to process SASS files but still keep the source folder structure. We don't want them to be minified/concatenated into one main file. For example if I have:
src/
components/
_header.scss
_sidebar.scss
_card.scss
Can I tell it to process them into:
dist/
components/
header.css
sidebar.css
card.css
gulp.task('styles:dist', () => {
return gulp
.src('./src/styles/**/*.+(scss|sass|css)', { base: './' })
.pipe(
sass({
outputStyle: 'expanded',
}).on('error', sass.logError)
)
.pipe(gulp.dest('./dist'));
});
Thanks in advance!
First install cleanCSS gulp plugin then run your task for convert scss or sass or less files to css then use css task for convert all css files to one minified and merge css file.
var cleanCSS = require('gulp-clean-css');
gulp.task('css', () => {
return gulp.src('./src/styles/**/*.css')
.pipe(cleanCSS({
compatibility: 'ie8',
level: {
1: {
specialComments: 0,
},
},
}))
.pipe('./dist'))
});
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