How to run converted .asm code from .c using 'gcc' in Emu8086

Question

I am new here and I converted code from C language to asm. However, it doesn't look like normal code in asm language. So my question is how can I convert a code from C(or C++) language to Assembly language, that the converted asm code could be run on Emu8086.

Here is a simple c code:

#include<stdio.h>

void Hello(){
printf("Hello world");
}
int main (){
Hello();
return 0;
}

Then I converted it with gcc -S test.c and here is the answer:

.file   "test1.c"
    .section    .rodata
.LC0:
    .string "Hello world"
    .text
    .globl  Hello
    .type   Hello, @function
Hello:
.LFB0:
    .cfi_startproc
    pushq   %rbp
    .cfi_def_cfa_offset 16
    .cfi_offset 6, -16
    movq    %rsp, %rbp
    .cfi_def_cfa_register 6
    leaq    .LC0(%rip), %rdi
    movl    $0, %eax
    call    printf@PLT
    nop
    popq    %rbp
    .cfi_def_cfa 7, 8
    ret
    .cfi_endproc
.LFE0:
    .size   Hello, .-Hello
    .globl  main
    .type   main, @function
main:
.LFB1:
    .cfi_startproc
    pushq   %rbp
    .cfi_def_cfa_offset 16
    .cfi_offset 6, -16
    movq    %rsp, %rbp
    .cfi_def_cfa_register 6
    movl    $0, %eax
    call    Hello
    movl    $0, %eax
    popq    %rbp
    .cfi_def_cfa 7, 8
    ret
    .cfi_endproc
.LFE1:
    .size   main, .-main
    .ident  "GCC: (Debian 6.3.0-18+deb9u1) 6.3.0 20170516"
    .section    .note.GNU-stack,"",@progbits

Answer 1

Emu8086 does what it says on the tin: it emulates an Intel 8086 processor. The assembly that GCC has produced is for your host machine (since you haven't told it to do otherwise), which evidently uses an x86-64 instructions set. The 8086 can't understand most of these instructions. You need to cross-compile it to an x86 16-bit real-mode executable. The -m16 option on GCC will generate 16-bit code, but it apparently still uses 32-bit registers (EAX, etc.). So you will have to find a compiler that targets the basic 8086 instruction set.