How to access universal link in iOS application?

Question

I am working with universal link to open iOS application and on this basis of link data I have to open viewcontroller in my iOS application.

I am using Xcode 10.0. And running application on iOS 12.0 (iPhone 7 Plus).

This is my universal link: https://en5vz.app.goo.gl/kjvaHzXrLMNBEDtG7

When I tap on this link then application is launched but method given below is not being called:

private func application(_ application: UIApplication, continue userActivity: NSUserActivity,
restorationHandler: @escaping ([Any]?) -> Void) -> Bool {

    print("\(#function) ---- \(userActivity.webpageURL)")
    if #available(iOS 11.0, *) {
        print("\(#function) ---- \(userActivity.referrerURL)")
    } else {
        // Fallback on earlier versions
    }


    if let incominURL = userActivity.webpageURL{

        let linkHandled = DynamicLinks.dynamicLinks()?.handleUniversalLink(incominURL, completion: { (dynamiclink, error) in

            if let dynamiclink = dynamiclink, let _ = dynamiclink.url{

                self.handleIncomingDynamicLink(dynamiclink: dynamiclink)
            }

        })
        return linkHandled!

    }

    return false

}

I am not able to figure out what is the exact issue.

Answer 1

This is an old question, but for anyone looking, the missing component here is the app-site-association file: https://developer.apple.com/documentation/uikit/core_app/allowing_apps_and_websites_to_link_to_your_content/enabling_universal_links

Take the following steps to associate your app and website for universal links:

1. Add the Associated Domains Entitlement to your app. Include all domains your app will support using the applinks service prefix. See Add the Associated Domains Entitlement.
2. Add an Apple App Site Association file to your website. See Add the Apple App Site Association File.
3. Add the applinks key to the Apple App Site Association file. Specify the sections of your website each of your apps will handle.

You've done step 1 (and step 0, which is setting up the code in your app), but steps 2 and 3 are missing.

Answer 2

I hope this help those in future facing this. I had the same problem where I could open the link to my website using ios App but could not log. I found out later that it was the @escaping [Any]? part that caused it. I changed my code to this instead: @escaping ([UIUserActivityRestoring]?) and it logged to the Xcode console.

func application(_ application: UIApplication, continue userActivity: 
NSUserActivity, restorationHandler: @escaping ([UIUserActivityRestoring]?) -> Void) -> Bool {
        print("Continue User Activity called: ")
        if userActivity.activityType == NSUserActivityTypeBrowsingWeb {
            let url = userActivity.webpageURL!
            print(url.absoluteString)
            //handle url and open whatever page you want to open.
        }

        return true
    }

Answer 3

For deep linking I would expect it to call the open url function:

func application(_ app: UIApplication, open url: URL, options: [UIApplication.OpenURLOptionsKey : Any] = [:]) -> Bool

Does that not work for you?