I know how to create a standard promise and use async/await to it but how can I await jquery promise().done() with typescript?
Current:
$('#sun').hide('slide', {direction:'right'}, 200).promise().done(function () {
$('#rain').show('slide', {direction:'left'}, 200).promise().done(function () {
console.log('ok!');
});
});
I would like to do in this way but it does not work:
await $('#sun').hide('slide', {direction:'right'}, 200).promise().done();
await $('#rain').show('slide', {direction:'left'}, 200).promise().done();
console.log('ok!');
Try removing the done()
call from the ends of your promise()
calls. Without specifically looking into the jQuery promise implementation I would imagine calling done()
without an argument returns undefined
or an otherwise unawaitable result, so you're trying to await undefined
.
Try awaiting the promise()
call instead:
await $('#sun').hide('slide', {direction:'right'}, 200).promise();
await $('#rain').show('slide', {direction:'left'}, 200).promise();
console.log('ok!');
A jquery promise works in the same manner as a vanilla promise
An example on how it works, convert this:
var div = $( "<div>" ); div.promise().done(function( arg1 ) { // Will fire right away and alert "true" console.log( this === div && arg1 === div ); });
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
to this:
var div = $( "<div>" ); async function run(){ const arg1 = await div.promise(); console.log(arg1 === div ); } window.onload = run;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
Solution:
await $('#sun').hide('slide', {direction:'right'}, 200).promise();
await $('#rain').show('slide', {direction:'left'}, 200).promise();
console.log('ok!');
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