Returning nodes with specific relationship

Question

I have a db of drugs and manufacturers and I want to find all manufacturers who have produced multiple drugs. How can I get only the manufacturers and the drugs they have produced?

I'm currently using

match (a:Brand), (c:Manufacturer) where size((c)-[:PRODUCED]->()) >1 return a,c;

which returns manufacturers with more than one drug produced but also all drugs, regardless of manufacturer

Answer 1

This query uses the aggregating function , COLLECT , to return a record for each manufacturer who makes multiple brands, along with a collection of those brands:

MATCH (m:Manufacturer)-[:PRODUCED]->(b:Brand)
WITH m, COLLECT(b) AS brands
WHERE SIZE(brands) > 1
RETURN m, brands;

Answer 2

听起来您只需要选择制造商，就像这样：

MATCH (c:Manufacturer) WHERE size((c)-[:PRODUCED]->()) > 1 RETURN c;