PHP : How to get value from DB to already created textbox
Question
Background
I am a complete beginner to web designing and i am using PHP and mySQL.
Code in hand
This is my HTML file named UserRegistration.php
<?php
session_start();
?>
<html>
<body>
<script>
function FillRecord(Id)
{
$.ajax({
type: "POST",
url: "Algorithm/UserRegistration-FillUserRecords.php",
data:'Id='+Id,
success: function(data)
{
document.forms["Frm_User"].elements["txtName"].value = "";
document.forms["Frm_User"].elements["txtFName"].value = "";
document.forms["Frm_User"].elements["txtMName"].value = "";
}
});
}
</script>
<form id="Frm_User" name="Frm_User" method="POST" action="Algorithm/UserRegistration-SaveDetails.php">
<label for="txtName">Name</label>
<input type="text" name="txtName" placeholder="Name" required>
<label for="txtFName">Father Name</label>
<input type="text" name="txtFName" placeholder="Father Name" required>
<label for="txtMName">Mother Name</label>
<input type="text" name="txtMName" placeholder="Mother Name" required>
</form>
<input type="button" onclick="FillRecord(1);">//1 is fixed at the moment
</body>
</html>
This is my PHP class named UserRegistration-FillUserRecords.php
<?php
session_start();
include_once 'Connection.php';
if ($dbcon->connect_error)
{
die("Connection failed: " . $dbcon->connect_error);
header('Location: ../UserRegistration.php');
exit();
}
//Search data from database on all fields except "SNo"
//----------------------------------------------------------------------------
$sql = "Select * from usertable where id=".$_POST["Id"];
$result = $dbcon->query($sql);
$rows = array();
foreach ($result as $RowRecord)
{
$_SESSION['UserRegistration_txtName'] = $RowRecord["Name"];
$_SESSION['UserRegistration_txtFName'] = $RowRecord["FName"];
$_SESSION['UserRegistration_txtMName'] = $RowRecord["MName"];
}
exit();
?>
The Algorithm/UserRegistration-SaveDetails.php is used to save the user details into database which is working perfectly.
Problem
I want to show the data which is being retrieved by UserRegistration-FillUserRecords.php into UserRegistration.php 's already created textbox when the function FillRecord is called but i have no clue as to how to assign the session variable value to my input boxes.
I Tried
1) alert(<?php echo $_SESSION['UserRegistration_txtName']; ?>); but the statement doesn't seem to work even when i have used
2) success: function(data) in AJAX reponse has the value which i need but when i echo it, it shows the value in continuation like:-
abc
----------------
a (Name)
b (Father Name)
c (Mother Name)
and i cant seperate it as the string can be anything, it can be full of comma's, new line characters and any special symbols
1 answers
solution1
1 ACCPTED 2019-01-11 16:20:06
Your PHP code doesn't actually output those session variables you've created to the browser. To do that, you need something like this (I'm using JSON as the format in which to send the data, as it's easiest to work with on the receiving end).
foreach ($result as $RowRecord)
{
$_SESSION['UserRegistration_txtName'] = $RowRecord["Name"];
$_SESSION['UserRegistration_txtFName'] = $RowRecord["FName"];
$_SESSION['UserRegistration_txtMName'] = $RowRecord["MName"];
}
// Create an array to send the data
$data = [
'Name' => $_SESSION['UserRegistration_txtName'],
'FName' => $_SESSION['UserRegistration_txtFName'],
'MName' => $_SESSION['UserRegistration_txtMName']
];
// Tell the browser that a JSON data file is coming
header('Content-type: application/json');
print json_encode($data);
exit();
Your jQuery AJAX handler function can then easily populate the form with these values:
function FillRecord(Id)
{
$.ajax({
type: "POST",
url: "Algorithm/UserRegistration-FillUserRecords.php",
data:'Id='+Id,
dataType: "json", //Add this so data comes back as an Object
success: function(data)
{
document.forms["Frm_User"].elements["txtName"].value = data.Name;
document.forms["Frm_User"].elements["txtFName"].value = data.FName;
document.forms["Frm_User"].elements["txtMName"].value = data.MName;
}
});
}
I hope I've correctly understood (and satisfied) what you want to achieve, please feel free to say if not.
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