Let's say I have:
const AddItemButton = React.memo(({ onClick }) => {
// Goal is to make sure this gets printed only once
console.error('Button Rendered!');
return <button onClick={onClick}>Add Item</button>;
});
const App = () => {
const [items, setItems] = useState([]);
const addItem = () => {
setItems(items.concat(Math.random()));
}
return (
<div>
<AddItemButton onClick={addItem} />
<ul>
{items.map(item => <li key={item}>{item}</li>)}
</ul>
</div>
);
};
Any time I add an item, the <AddItemButton />
gets re-rendered because addItem is a new instance. I tried memoizing addItem:
const addItemMemoized = React.memo(() => addItem, [setItems])
But this is reusing the setItems from the first render, while
const addItemMemoized = React.memo(() => addItem, [items])
Doesn't memoize since items
reference changes.
I can'd do
const addItem = () => {
items.push(Math.random());
setItems(items);
}
Since that doesn't change the reference of items
and nothing gets updated.
One weird way to do it is:
const [, frobState] = useState();
const addItemMemoized = useMemo(() => () => {
items.push(Math.random());
frobState(Symbol())
}, [items]);
But I'm wondering if there's a better way that doesn't require extra state references.
The current preferred route isuseCallback
, which is the same as your useMemo
solution, but with additional possible optimizations in the future. Pass an empty array []
to make sure the function will always have the same reference for the lifetime of the component.
Here, you also want to use the functional state update form , to make sure the item is always being added based on the current state.
const addItem = useCallback(() => {
setItems(items => [...items, Math.random()]);
}, []);
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