Is there a way to print lines from a file from n to m and than reverse their positions?

Question

I'm trying to print text from line 10 to 20 and then reverse their positions.

I've tried this:

sed '10!G;h;$!d' file.txt

But it only prints from 10 to end of the file. Is there any way to stop it at line 20 by using only one sed command?

Answer 1

Almost there, you just need to replace $!d with the 'until' line-number

sed -n '10,20p' tst.txt
// Prints line 10 <--> 20

sed -n '10!G;h;20p' tst.txt
// Prints REVERSE line 10 <--> 20

output:

20
19
18
17
16
15
14
13
12
11
10

tst.txt:

1
2
3
4
...
19
20

Info

Answer 2

You can use this to print a range of lines:

sed -n -e 10,20p file.txt | tac

tac will reverse the order of the lines

Answer 3

对于那些没有TAC的人（例如那些Mac用户）：

sed -n -e 10,20p file.txt | tail -r