How to remove empty dataframes in a list before using bind_rows()?

Question

I have a list of a mix of dataframes, tibble and empty list. How do I remove the tibble and empty list before applying bind_rows to append the rest of the data frames?

I tried using the delete.NULLs function but there was an error:

Error: could not find function "delete.NULLs"

Answer 1

We can use discard

library(purrr)
discard( lst1, ~is.vector(.x) || is.null(.x)|is_tibble(.x) )

EDIT: From @ArtemSokolov's comments

---

Or from base R

out <-  Filter(function(x) !(is.vector(x) | is.null(x) |is_tibble(x)), lst1)
out
#[[1]]
#  col1
#1    1
#2    2
#3    3

#[[2]]
#  A B
#1 1 2
#2 2 3
#3 3 4
#4 4 5
#5 5 6

---

The delete.NULLs function is not found in base R . But, it could be created with a combination of is.null and negate ( ! ).

data

lst1 <- list(data.frame(col1 = 1:3), NULL, tibble(col1 = 1:5, 
             col2 = 2:6), NA, data.frame(A = 1:5, B = 2:6))

Answer 2

Using @akrun data:

lst1[unlist(lapply(lst1, function(x) !(is.null(x) | is_tibble(x))))]

Regarding your question about NA :

lst1 <- list(data.frame(col1 = 1:3), NULL, tibble(col1 = 1:5, 
                                                  col2 = 2:6), data.frame(A = 1:5, B = 2:6), NA)

lst <-lst1[unlist(lapply(lst1, function(x) !(is.null(x) | is_tibble(x))))]

lst<-lst[!is.na(lst)]