I'm practicing for upcoming interviews and I'm trying to deserialise a binary search tree. I got it to work for serialising but I'm getting an argument number error but I don't see why.
I expect "5 2 1 # # # 35 18 7 # # 30 # # #" to be turned back into a tree.
Error:TypeError: _deserialize() takes exactly 2 arguments (3 given)
def __init__(self,value = None):
self.value = value
self.left_child = None
self.right_child = None
class BinarySearchTree:
def __init__(self):
self.root = None
def insert(self,value):
if self.root is None:
self.root = Node(value)
else:
self._insert(value, self.root)
def _insert(self, value, current_node):
if value < current_node.value:
if current_node.left_child is None:
current_node.left_child = Node(value)
else:
self._insert(value,current_node.left_child)
elif value > current_node.value:
if current_node.right_child is None:
current_node.right_child = Node(value)
else:
self._insert(value,current_node.right_child)
else:
print("Value already inserted!")
def serialize(self,serial):
if self.root is not None:
return ' '.join(self._serialize(self.root, serial))
def _serialize(self, current_node, serial): #Post order
if current_node is not None:
serial.append(str(current_node.value))
self._serialize(current_node.left_child, serial)
self._serialize(current_node.right_child, serial)
else:
serial.append("#")
return serial
def deserialize(self, serial):
vals = iter(serial.split())
return self._deserialize(self, vals)
def _deserialize(self, vals):
value = next(vals)
if value == "#":
return None
node = Node(int(value))
node.left_child = self._deserialize(vals)
node.right_child = self._deserialize(vals)
return node
tree = BinarySearchTree()
tree.insert(5)
tree.insert(2)
tree.insert(1)
tree.insert(35)
tree.insert(18)
tree.insert(7)
tree.insert(30)
root = Node(3)
serial = []
serial = tree.serialize(serial)
print(serial)
tree.deserialize(serial)
正如@Primusa指出的那样, return self._deserialize(self, vals)
应该是return self._deserialize(vals)
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.