How to combine Swashbuckle filters?

Question

What I need is using some condition to hide or show some properties of a model in Model|Example Value of response in Swagger UI.

How could this be realized? My condition is based on attributes on api actions and on properties of a DTO. So, fe, if an action provides an attribute then we should only see the tagged properties in Swagger UI.

Answer 1

Solved. You only need to implement IOperationFilter and register it. This stuff allows you to show customized different examples for the same model.

---

DTO

public class MyDTO
{
    public int Id { get; set; }

    [ShortModelMember]
    public string Name { get; set; }
    ...
}   

Method in API controller

[HttpGet]
[ReturnShortModel]
public MyDTO GetSmthg()
{
    return MyDTO.GetExample();
}   

Swagger's custom operation filter

public class SwaggerExcludeFilter : IOperationFilter
{
    public void Apply(Operation operation, SchemaRegistry schemaRegistry, ApiDescription apiDescription)
    {
        if (!apiDescription.GetControllerAndActionAttributes<ReturnShortModelAttribute>().Any())
        {
            return;
        }

        var responseType = apiDescription.ResponseDescription.DeclaredType;
        var description = $"OK (uses a short model of {responseType})";
        var props = responseType
                    .GetProperties()
                    .Where(p => p.GetCustomAttributes(typeof(ShortModelMemberAttribute)).Any())
                    .ToDictionary(p => p.Name, p.PropertyType.Name);
        }

        operation.responses.Clear();
        operation.responses.Add("200", new Response
        {
            description = description,
            schema = new Schema
            {
                example = props,
            },
        });
    }
}   

And finally

c.OperationFilter<SwaggerExcludeFilter>();